Potassium per chlorate is prepared by the following sequence of reactions:
Cl2(g) + 3 KOH (aq) ----------> KCl (aq) + KCl(aq) + H2O (l)
3KClO(aq) ----------> 2 KCl (aq) + KClO3 (aq)
4 KClO3 (aq) ---------> 3 KClO4 (aq) + KCl(aq)
Explain what mass of Cl2 (g) is needed to form the 234 kg of KClO4?