2Na(s) + 2H2O(l) ---->2NaOH (aq)+H2(g)
delta H= -365.6 kJ and delta S= -15.3 J/K
Explain what is the maximum amount of work that could be done when 2.47 moles of Na(s) reacts at 295 K, 1 atm?
Presume that delta H and delta S are independent of temperature.