Explain how would the enol proton signal look/behave for the equilibrium below if exchange is 1) slow relative to the NMR time scale 2) fast relative to the NMR time scale 3) between slow and fast given that Keq is 2.
KeqtBu-(C-OH)=C-(C=O)-Ph <=> tBu-(C=O)-C=(C-OH)-Ph