Explain how much dry solute would you take to prepare each of the subsequent solutions from the dry solute and the solvent?
A.) 130 mL of 0.440 M KCl
B.) 116 g of 0.220 m NaNO3
C.) 116 g of 1.7 % KCl solution by mass
D.) How much solvent would you take to prepare the solution in part B?
E.) How much solvent would you take to prepare the solution in part C?