Explain how many molecules of H2S are required to form 79.0 g of sulfur according to the subsequent reaction? Presume excess SO2.
2 H2S(g) + SO2(g) ? 3 S(s) + 2H2O(l)
9.89 × 1023 molecules H2S
5.06 × 1025 molecules H2S
2.44 × 1023 molecules H2S
1.48 × 1024 molecules H2S
3.17 × 1025 molecules H2S