Evaluate integrals a nbspintegral of dz1 - z 3 nbsp c is
Evaluate integrals :
a) integral of [dz/(1 - z )^3 ] , C is circle |z| = 1/2
b) integral of [e^z/(1 - z )^3 ] dz , C is circle |z - 1| = 1/2
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1nbspprove using propositional calculus thatpvqgtr ltgt prvqr2nbspgiven an example of a conjunction that is a tautology
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evaluate integrals a nbspintegral of dz1 - z 3 nbsp c is circle nbspz 12bnbspintegral of ez1 - z 3 dz nbsp c is
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