During the process there is no change in internal energy a


An ideal gas that expands isothermally from V1 to V2 does an amount of work equal to kNT ln (V2/V1) . Suppose that a given ideal gas at an initial pressure of 1.35×105 N /m^2expands isothermally at a temperature of 300K. It stops expanding when it reaches a volume of 0.55m^3 at a pressure of 1.01×105 N /m^2. During the process there is no change in internal energy.

a. Calculate the initial volume of the gas.

b. Calculate the work done by the expansion.

c. Calculate the change in entropy of the gas.

Solution Preview :

Prepared by a verified Expert
Physics: During the process there is no change in internal energy a
Reference No:- TGS02776786

Now Priced at $15 (50% Discount)

Recommended (94%)

Rated (4.6/5)