Dissolve an aluminum soft-drink can in an aqueous base 2 al
Dissolve an aluminum soft-drink can in an aqueous base. 2 Al (s) + 2 KOH (aq) + 6H20 (l)---> 2KAI(OH)4(aq) + 3H(g) If you place 2.05g of aluminum in a beaker with 185 mL of 1.35 M KOH, will any aluminum remain? What mass of KAI(OH)4 is produced?
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A 200 foot long, 2.5 feet in diameter, straight, corrugated metal storm drain pipe, is used to drain a parking lot. The elevation difference between the pipe ends is 8 feet. What velocity would be expected
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Dissolve an aluminum soft-drink can in an aqueous base. 2 Al (s) + 2 KOH (aq) + 6H20 (l)---> 2KAI(OH)4(aq) + 3H(g) If you place 2.05g of aluminum in a beaker with 185 mL of 1.35 M KOH, will any aluminum remain. What mass of KAI(OH)4 is produced
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Two monitoring wells were constructed in an unconfined aquifer. The wells are separated by a distance of 250 ft. The water surface elevations in the up-gradient and down-gradient wells were 101.00 and 100.85 ft, respectively.
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The acidic anion reacts with strong bases according to the following net ionic equation HC8H4O4-(aq) + OH- (aq)--->C8H4O4-2(aq) + H2O(l) If a 0.902g sample of KHC8H4O4 is dissolved n water and titrated to the equivalence point
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