Suppose that in starting a car on a cold morning a current of 125 amperes is drawn for 15.0 seconds from a cell of the type described above. How many grams of Pb would be consumed? The equation for the reaction that occurs is:
Pb(s) + PbO2(s) + 2HSO4-(aq) + 2H+ (aq)→ 2PbSO4(s) +2H2O(l)