Based on the equilibrium constant values for the following reactions:
Cd(NH_3)42+ (aq) <->Cd2+ (aq) + 4 NH3 (aq) K=1.0x10-7
CdS (s) <-> Cd2+ (aq) + s2-(aq) K= 3.6x 10-29
Determine the value of the equilibrium constant for the reaction
CdS (s) + 4 NH3 (aq) <-> Cd(NH3)42+ (aq) + S2+(aq)