Determine the thermodynamic equilibirum constant, Chemistry

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Determine the thermodynamic equilibirum constant

At 298K, S2F4(g) partially decomposes to SF2 (g). at equilibirum the partial pressure of SF2(g) is 8.4x10^-2torr and the partial pressure of S2F4(g) is 36.8 torr.

S2F4(g)<-->2SF2(g)

Determine the thermodynamic equilibirum constant for this decomposition.

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Chemistry: Determine the thermodynamic equilibirum constant

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At 298K, S2F4(g) partially decomposes to SF2 (g). at equilibirum the partial pressure of SF2(g) is 8.4x10-2torr and the partial pressure of S2F4(g) is 36.8 torr.

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Chemistry: Determine the thermodynamic equilibirum constant

Reference No:- TGS0842246

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Recent Questions Asked Chemistry

Q : Find the molar enthalpy of combustion for ethanol

Q : Number of orange candies

Q : Average in inventory

Q : Mean and the standard deviation for the number

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Q : Find the mean and standard deviation

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Chemistry: Determine the thermodynamic equilibirum constant

Reference No:- TGS0842246

Recent Questions Asked Chemistry

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