Bromine and mercury will react with each other to form mercury (II) bromide:
Hg(l)+Br2(l)-->HgBr2(s)
Compute an experiment where 10.0 g Hg is reacted with 9.00 g Br2.
1. Determine the limiting reactant under these conditions?
2. Determine what mass of HgBr2 can be formed from this reaction under these conditions?
3. Determine the numbers of moles of which reactant will be left un-reacted?