A soluble iodide was dissolved in the water. Then an excess of silver (I) nitrate, AgNO3 wad added to totally precipitate out all of the iodide ion as silver (I) iodide, AgI. If 1.545 grams of soluble iodide yielded 2.185 of silver(I) iodide, then,
1. Determine the numbers of moles of I- are in the original soluble iodide sample?
2. Determine the numbers of grams of I- are in the original soluble iodide sample?
3. Calculate the percentage by mass of I- in the original soluble iodide sample?