The balanced equation for the titation is
16 H+ + 2MnO4- +5C2O42- ---> 2Mn2+ +10CO2 + 8H2O
In a titration a 1.0 g sample of plant material containing oxalic acid, H2C2O4, requires 24.0 mL of 0.0100 M KMnO4 to reach the equivalence point. Describe the percentage of oxalic acid in the sample?