![2370_The straight line of charge has uniform positive charge density.jpg](https://secure.tutorsglobe.com/CMSImages/2370_The%20straight%20line%20of%20charge%20has%20uniform%20positive%20charge%20density.jpg)
You have two insulators. One is a straight line of charge, and the other is an arc of charge (a partial circle), as pictured above. The straight line of charge has uniform positive charge density λ1 = A and is a distance d from point P. The arc on the right is centered at point P, has radius R and positive charge density λ2= B and extends from θ= -Π/3 to Π/3
(a) Derive an expression for the electric field at point P due to the line of charge. Include both magnitude and direction. (Your answer should not include λ or x.)
(b) Derive all expression for the electric field at point P due to the arc of charge. Include both magnitude and direct ion. (Your answer should mu include λ or θ.)
(c) What is the total field at point P? (Note: if you did not get one of the previous answers use |Eline| = kA/L or |Earc|=kB/2R)
(d) If R = L = d, for what ratio of A and B it is the electric field at point P=0 or is it never equal to 0?