derivative for parametric equationsdxdy dxdt
Derivative for Parametric Equations
dx/dy = (dx/dt) / (dy/dt) , given dy/dt ≠ 0
Why would we wish to do this? Well, remind that in the arc length section of the Applications of Integral section we in fact needed this derivative on occasion.
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as we have seen in during epinephrine hormonal control or glucagon dephosphorylated phosphorylase kinase is activated by
eliminate the parameter from the subsequent set of parametric equationsx t2 ty 2t - 1solutionone of the very easy ways to eliminate the parameter
in chemistry and particularly in biochemistry the fatty acid is a carboxylic acid with a long aliphatic tail chain that is either saturated
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derivative for parametric equationsdxdy dxdt dydt given dydt ne 0why would we wish to do this well remind that in
find out the tangent lines to the parametric curve specified byx t5 - 4t3y t2at 04solution note that there is actually the potential for more than
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horizontal tangents for parametric equations horizontal tangents will take place where the derivative is zero and meaning of this is that well get
fatty acids have four main biological roles1 they are used to create sphingolipids and glycerophospholipids which are necessary elements of
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