Data: 2Ba(s) + O2(g) => 2BaO(s) ?H = -1107.0 kJ Ba(s) + CO2(g) + 1/2O2(g) => BaCO3(s) ?H = -822.5 kJ Given the data above, calculate ?H for the reaction below. Reaction: BaCO3(s) => BaO(s) + CO2(g)====== a. -1929.5 kJ b. -1376.0 kJ c. -284.5 kJ d. 269.0 kJ e. 537 kJ