Question- 1)
Cr2O7 2- + 6S2O3 2- + 14H+ ? 2Cr 3+ + 3S4O6 2- + 7H2O
a) Why is Cr6+ reduced in the following reaction?
b) Why is S2+ oxidized in the following reaction?
c) Why is Cr2O7 2- the oxidizing agent?
d) Why is S2O3 2- the reducing agent?
2)
14H+ + Cr2O72- + 3Ni ? 3Ni2+ + 2Cr3+ + 7H2O
a) Why is Ni the reducing agent
b) Why is Cr2O7 2- the oxidizing agent
Solve the above problem and provide steps with explanation