Convert the following C program to MIPS program. Assuming that i, j, k, f, are stored in registers $s0, $s1, $s2, $s3 already. Show work.
A) f = i + j +k
B) f = i + (j - 2)
C) f = i + (-j + 2) (Hint: $zero)
D) f = i*4 (Hint: relationship between multiplication and shift)
E) f = i/8 +3