Convert the following C program to MIPS program. Assuming that i, j, k, f, are stored in registers $s0, $s1, $s2, $s3 already.
1) f = i + j + k +1;
2) f = i - 2;
3) f = i;
4) f = -i;
5) f = i - ( j + k );
6) f = i & j;
7) f = i/16 (Hint: relationship between multiplication/division and shift)
8) f = i*2 - 3;
9) f = i++;
10) f = ++i;