Problem: Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two populations, individuals who drink alcohol and individuals who do not drink alcohol. The mean ALT levels for the individuals who do not drink alcohol is 35 with a standard deviation of 15, and 41 individuals were in the sample. The mean ALT levels for individuals who drink alcohol is 73 with a standard deviation of 21, and 43 individuals were in the sample. Construct and interpret a 95% confidence interval demonstrating the difference in means for those individuals who drink alcohol when compared to those who do not drink alcohol.
- The researchers are 95% confident that the true mean difference in ALT values between the population of drinkers and population of non-drinkers is between 24.22 and 39.78.
- The researchers are 95% confident that the true mean difference in ALT values between the population of drinkers and population of non-drinkers is between 24.33 and 39.67.
- The researchers are 95% confident that the true mean difference in ALT values between the population of drinkers and population of non-drinkers is between 30.16 and 45.84.
- The researchers are 95% confident that the true mean difference in ALT values between the population of drinkers and population of non-drinkers is between 29.43 and 44.57.