Compute the standard enthalpy of formation of gaseous diborane (B2H6) using the following thermo chemical information:
4B (s) + 3O2 (g) ==> 2B2O3 (s) change in H= -2509.1 kJ
2H2 (g) + O2 (g) ==> 2H2O (I) change in H= -571.7 kJ
B2H6 (g) + 3O2 (g) ===> B2O3 (s) + 3 H2O (I) change in H= -2147.5