Compound interest if 5000 is invested at 135 compounded, Engineering Mathematics

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Compound interest if 5000 is invested at 135 compounded

Question: Compound interest If $5000 is invested at 13.5%, compounded continuously, then the future value S at any time t (in years) is given by

S = 5000e^0.135t.

(a) What is the amount after 9 months?

(b) How long will it be before the investment doubles?

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Engineering Mathematics: Compound interest if 5000 is invested at 135 compounded

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