Consider the following balanced equation: 3Ca(ClO3)2(aq) + 2Li3PO4(aq) → Ca3(PO4)2(s) + 6LiClO3(aq)
If 11.9 moles of Ca(ClO3)2(aq) and 13.8 moles of Li3PO4(aq) are allowed to react, and the percent yield is 51.3%, how many moles of LiClO3(aq) will actually be produced?