Cate the heat lost by the hot water see the

Question

VI (ml)	150.0
VF (ml)	165.5
TI (?C)	68.0
TF (?C)	57.0
?V (ml)	15.5
?T (?C)	-11.0

1. Calculate the heat lost by the hot water. (See the equation in the Introduction.) Express your answer in calories and Joules. Show your work.

• Heat(cal)=(mass(g))(C_p)(?T)
• Heat=(150g)( 1cal/g^oc)(11^oC)
• Heat=1650cal
• 1cal=4.184J
• 1650cal=394J

2. Using the volume of ice melted, convert to mass of ice melted using the density of water of 1 g/mL.

• M=DV
• M=(1g/ml)(15.5ml)
• M=15.5g

3. Convert mass of ice melted to moles of ice melted.

• Moles=g(1mol/molar mass)
• Moles=15.5g(1mol/18.0g)
• =.861mol

4. Calculate the molar heat of fusion of ice in kJ/mol.