case 1 suppose we have two terms 7ab and


Case 1: Suppose we have two terms 7ab and 3ab. When we multiply these two terms, we get 7ab x 3ab = (7 x 3) a1 + 1 . b1 + 1  ( Therefore, xm . xn = xm + n) = 21a2b2. The product of 7ab x 3ab will be the same as that of 3ab x 7ab. Irrespective of the order of multiplication, the product of two positive terms will be a positive term.

Similarly, the product of 8a2b and 3a2b

                   = (8 x 3) a2 . ab . b

                   = 24 a2+2 b1+1

                   = 24 a4 b2

Case 2:  Suppose we have to compute the product of -7ab and -3ab, it will be equal to (-7 x -3) a2b2 = 21a2b2, i.e. multiplication of two negative quantities gives us a positive quantity.

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Mathematics: case 1 suppose we have two terms 7ab and
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