Calculate thermal conductivity of material


Solve the below problem:

Q: To measure thermal conductivity, two similar 1-cm-thick specimens are placed in an apparatus shown in the accompanying sketch. Electric current is supplied to the 6-cm by 6-cm guarded heater, and a wattmeter shows that the power dissipation is 10 watts (W). Thermocouples attached to the warmer and to the cooler surfaces show temperatures of 322 and 300 K, respectively. Calculate the thermal conductivity of the material at the mean temperature in Btu/(h ft°F) and W/(m K).

GIVEN

Thermal conductivity measurement apparatus with two samples as shown

Sample thickness (L) = 1 cm = 0.01 cm

Area = 6 cm A=6 cm = 36 cm2 = 0.0036 m2

Power dissipation rate of the heater (qh) = 10W

Surface temperatures

Thot = 322 K and Tcold = 300 K

ASSUMPTIONS

One dimensional, steady state conduction

No heat loss from the edges of theapparatus

645_Heater.jpg

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Electrical Engineering: Calculate thermal conductivity of material
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