Calculate the volume change (in Liters) during the oxidation of sulfur dioxide in which ?E = -849.700 kJ and ?H = -852.373 kJ at a constant pressure of exactly one atm and constant temperature. 2 SO2(g) + O2(g) ? 2 SO3(g) The product of pressure and volume change should give units of L*atm. It can be shown that 1 L*atm = 101 J.