Calculate the pH of each of the following solutions:
(a) 0.1000 M Propanoic acid (HC3H5O2, Ka= 1.3 x 10^-5)
(b) 0.1000 M sodium propanoate (NaC3H5O2)
(c) 0.1000 M HC3H5O2 and 0.1000M NaC3H5O2
(d) After 0.020 mol of HCl is added to 1.00 L solution of (a) and (b) above.
(a) pH=1.70
(b) pH=5.49
(e) After 0.020 mol of NaOH is added to 1.00 L solution (a) and (b) above.
(a) pH=4.29
(b) pH=12.30