Calculate the number of moles of ions present in 66.8 g of a solution that is 2.11% Fe(NO3)3 by mass.
a) There are 0.00583 moles of ions in this solution.
b) There are 0.276 moles of ions in this solution.
c) There are 0.00146 moles of ions in this solution.
d) There are 0.0233 moles of ions in this solution.
e) There are 1.10 moles of ions in this solution.