At 298 K and 1 atm, the (delta H vap) and (delta Svap) of PCl(l) equal 32.7kj mol^- 1 respectively. By determing deltaGva, expalin why PCl(l) does not biol under these conditions.
a) calculate the normal boiling point of Pcl(l).
b) determine the vapour pressure of PCl3 (l) at 298K.