A 225 mg sample of diprotic acid is dissolved in enough water to make 250 ml of a solution. The pH of the solution is 2.06. A saturated solution of calcium hydroxide (Ksp=5.5*10^-6) is prepared by adding excess calcium hydroxide to pure water and then removing the undissolved solid by filtration.Enough of the saturated calcium hydroxide solution is added to the solution of the acid to reach the second equilvalence point. The pH of the second equilvanece point is 7.96. The first dissociation constant for the acid (Ka1) is 5.90*10^-2. The solutions are at 25 degrees celcius and that Ka1 is at least 1000 times greater than Ka2. (can someone show me how to start)
1.) Calculate the molar mass of the acid.
2.) Calculate the second dissociation constant for the acid, Ka2.