Consider the following parallel plate capacitor
Givens:
top plate 1 meter wide by 1 meter deep by 10 mm thick bottom plate 1 meter wide by 1 meter deep by 10 mm thick
gap 12 mm applied voltage 1000 volts containing different materials inside the gap as follows:
a) 12 mm of vacuum (Ke = 1)
b) 1 mm of vacuum, 10 mm of dielectric (Ke = 4), 1 mm of vacuum
c) 1 mm of vacuum, 10 mm of paraelectric (Ke = 20), 1 mm of vacuum
d) 1 mm of vacuum, 10 mm of ferroelectric (Ke = 300), 1 mm of vacuum
e) 0.3 mm vacuum, 3.8 mm dielectric, 3.8 mm paraelectric, 3.8 mm ferroelectric, 0.3 mm vacuum
CALCULATE each of the following for a) thru e) cases above:
1) Calculate E, D and P inside the vacuum gaps and inside each material
2) Calculate the resulting capacitance for each case
3) Calculate the force of electrical attraction when the material is in the center of the capacitor
4) Calculate the work required to pull the material out of the gap.