When the radiation is directed at 254.4 nm of a mercury lamp on asample of Cesium, electrons are ejected with a speed of 0.589 x 10^ 6 m / s. This same radiation ejects electrons from a sample ofRubidium at a speed of 0.495 x 10 ^ 6 m / s.
a) Calculate the first ionization energy of these 2 elements.Expressing them in electro volts (eV)
b) Knowing that a second ionization energy of Cesium is 25.05 eV,what is the wave length of UV light required to eject electronsfrom the 2nd ionization of a sample of cesium with a speed of 0.2 x10 ^ 6 m / s?.