Calculate the electron affinity in kJ/mol for X in the hypothetical ionic compound MX from the information given below.
IE1(M) = 432 kJ/mol
M(s) => M(g) ?Ho = 78.6 kJ/mol
?Hof(MX) = -143.9 kJ/mol
X2(g) => 2X(g) ?H = 238 kJ
?Hlattice (MX) = -715 kJ/mol
IE1 (X) = 271 kJ/mol