In a coffee-cup calorimeter, 1 mol KOH and 1 mol HBr initially at 23.5 oC (Celsius) are mixed in 100g of water to yield the following reaction: KOH + HBr ? K+(aq) + Br-(aq) + H2O(l) After mixing the temperature rises to 78.2 oC. Calculate the change in enthalpy of this reaction. Specific heat of the solution = 4.184 J/(g oC) State your answer in kJ with 3 significant figures. Don't forget to enter the unit behind the numerical answer. The molecular weight of KOH is 56.2 g/mol, and the molecular weight of HBr is 80.9 g/mol.