Calculate Ecell for the following electrochemical cell at 25 °C Pt(s) | H2(g, 1.00 atm) | H+(aq, 1.00 M) || Pb2+(aq, 0.150 M) | Pb(s) given the following standard reduction potentials.
Pt(s) | H2(g, 1.00 atm) | H+(aq, 1.00 M) || Pb2+(aq, 0.150 M) | Pb(s)
given the following standard reduction potentials.
Pb2+(aq) + 2 e- → Pb(s) E° = -0.126 V
2 H+(aq) + 2 e- → H2(g) E° = 0.000 V
I dont know which equation to flip and I am confused between cathode and anode.