C Program for FIND EVEN & ODD NO.S IN THE ARRAY
#include stdio.h>
#include string.h>
#include conio.h>
void main()
{
int i=0,j=0, l_e[100],l_o[100];
int a[100],odd=0,even=0,sum_even=0,sum_odd=0;
float avg_e=0,avg_o=0;
for(i=0;i<100;i++)
{
a[i]=0;
l_e[i]=0;
l_o[i]=0;
}
i=0; clrscr();
printf("\nENTER THE LIMIT OF ELEMENTS: ");
scanf("%d",&j);
for(i=0;i
{
printf("\nENTER THE NO %d: ",i+1);
scanf("%d",&a[i]);
if(a[i]%2==0)
{
sum_even=sum_even+a[i];
even++;
avg_e=sum_even/even;
l_e[i]=a[i];
}
else
{
sum_odd=sum_odd+a[i];
odd++;
avg_o=sum_odd/odd;
l_o[i]=a[i];
}
} i=0;
printf("\nTHE EVEN NO.S ARE %d",even);
printf("\nTHE ODD NO.S ARE %d",odd);
printf("\nTHE TOTAL OF EVEN NO.S ARE %d",sum_even);
printf("\nTHE TOTAL OF ODD NO.S ARE %d",sum_odd);
printf("\nTHE AVERAGE OF ALL EVEN NO.S IS %f",avg_e);
printf("\nTHE AVERAGE OF ALL ODD NO.S IS %f",avg_o);
getch();
}
OUTPUT :
ENTER THE NO 1 1 : 2
ENTER THE NO 1 2 : 6
ENTER THE NO 1 3 : 3
ENTER THE NO 2 1 : 4
ENTER THE NO 2 2 : 7
ENTER THE NO 2 3 : 8
ENTER THE NO 3 1 : 9
ENTER THE NO 3 2 : 1
ENTER THE NO 3 3 : 2
NO ARE IN ASCENDING ORDER
1 2 2
3 4 6
7 8 9