The following formula relates the distance (in feet) traveled by a vehicle during an emergency stop to the time (in seconds) it takes to arrive at a complete stop: S = 16t^2 740 = 16t^2 740 = 16 x t^2 740 = 16 x t^2 -16 = -16 x t^2 724 = t^2 At the scene of an accident, Bill uses skid marks to determine the braking distance of one of the vehicles involved was about 740 feet. What is the corresponding braking time?