At what height above the earth is the free-fall


Solve the following problem:

Problem I: At what height above the earth is the free-fall acceleration 25 % of its value at the surface? Assume Rearth = 6.37 × 106 m. 

Problem II: What is the speed of a satellite orbiting at that height? Assume Mearth = 5.98 × 1024 kg.

Can someone please explain what the heck is going on above problem?

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Physics: At what height above the earth is the free-fall
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