A pure shear deformation is applied to the square element as shown in the figure such that σ12 = σ21 is only nonzero stress component.
At load step n, the stress value was σ12 = 50, and there was no plastic deformation. At load step n + 1, incremental strain Δε12 = Δε21 = 0.005 is applied. Calculate stress components andeffective plastic strainatload step n + 1.
Use the following material properties: shear modulus μ = 1,000, plastic modulus H = 100, initial yield stress σY = 100.