At equilibrium the concentration of ammonia is 0153 m, Chemistry

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At equilibrium the concentration of ammonia is 0153 m

Question- A mixture consisting of 0.150 M N2(g) and 0.659 M H2(g) reacts and then reaches equilibrium according to the equation:

N2(g) + 3H2(g) ? 2NH3(g)

At equilibrium, the concentration of ammonia is 0.153 M. Calculate the concentration (molarity) of H2(g) at equilibrium to 3 decimal places.

Explain the each step. Explain the process and each step.

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Chemistry: At equilibrium the concentration of ammonia is 0153 m

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Chemistry: At equilibrium the concentration of ammonia is 0153 m

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