At 800 k kc for the following equalibrium is 42 x 10 -3, Chemistry

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At 800 k kc for the following equalibrium is 42 x 10 -3

At 800 k, Kc for the following equalibrium is 4.2 x 10 ^-3. 2HgO(s) <--> 2Hg(l) + O2(g), suppose 96.5 g of mercury(ll) oxide is placed in a sealed 3.50 vessel at 800 k. What is the partial pressure of oxygen gas at equalibrium?( R=0.0821 L(atm)/K(mol)

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Chemistry: At 800 k kc for the following equalibrium is 42 x 10 -3

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Chemistry: At 800 k kc for the following equalibrium is 42 x 10 -3

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