As part of an ANOVA that compares three treatments, you carry out Tukey pairwise tests at the overall 5% significance level. The Tukey tests find that µ1 is significantly different from µ2 but that the other two comparisons are not significant. You can be 95% confident that
![](https://test.transtutors.com/qimg/e2969a89-fb33-49d7-b4f9-41d76e3aeb60.png)
(b) just
there is not enough evidence to draw conclusions about the other pairs of means.
(c)
and this implies that it must also be true that ![](https://test.transtutors.com/qimg/ff20b4cf-58c7-4467-9aea-9dd6326f6d8f.png)