An LR circuit is hooked up to a battery as shown in the figure, which the switch initially open. The resistance in the circuit is R = 110 Ohm, the inductance is L=4.80H, and battery maintains a voltage of E=47.0V. At time t=0 the switch is closed.
What is the current through the circuit after the switch has been closed for t=2.66x10-2s?
What is the voltage across the inductor after the switch has been closed for t=2.66x10-2 seconds?