An empty drinking glass is held upside down just above the surface of water. A scuba diver carefully takes the glass, which remains upside down, to a depth of 10.3 meters below the surface so that a sample of air is trapped in the glass. Assume that the temperature of the water (and the trapped air) remains fixed at 15oC during the descent, and that the ambient pressure at the surface is Patm = 1.103×105 Pa. Assume air behaves as an ideal gas, and water behaves as an incompressible liquid. (Hint: the hydrostatic pressure increase is proportional to the diving depth as ?P=?H2Og ?h.) Answer the following at diving depth of 10.3 meters:
a. Provide a clearly labeled sketch of the situation and define system boundaries.
b. Clearly state your assumptions.
c. What is the final pressure in the glass?
d. What final fraction of the glass’s volume is filled with air?
e. Show the process on a P-v diagram.
f. If 0.2 grams of air are initially trapped within the glass, how much energy (heat) crosses the boundary of the system (air) during the process? Explain your answer.