Hello, need help with the following chem questions.
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 24.0 g of aluminum and 29.0 g of chlorine gas.
1. If you had excess chlorine, how many moles of aluminum chloride could be produced from 24.0 g of aluminum?
2. If you had excess aluminum, how many moles of aluminum chloride could be produced from 29.0 g of chlorine gas, Cl2?