At a certain temperature, 0.310 mol of PCl3(g) and 8.46 x 10-3 mole of PCl5(g) are placed into a 0.844 L flask. PCl5(g) is known to dissociate according to the following reaction:
PCl5(g) ? PCl3(g) + Cl2(g)
After equilibrium is established, the flask is found to contain 1.13 x 10-3 mol of Cl2. Calculate the value of the equilibrium constant, Kc, for the reaction at this temperature.
4.80 x 10-2
5.68 x 10-2
2.33 x 105
3.88 x 105
4.31 x 10-2