In a closed container, consider treating 1.0 mols CaCO3(s) with 1.0 L of 0.50 M HCl. After all reactions of consequence occur and equilibrium is established, solubility for CaCO3 in this system is much less than solubility for CaCO3 in water even though this system is considerably more acidic than the CaCO3/water system. Provide a brief, qualitative, chemically-sound explanation of these facts.