Acircular hole of radius 8470times10minus1 cm mustbe cut, Physics

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Acircular hole of radius 8470times10minus1 cm mustbe cut

Engineering Application Acircular hole of radius 8.470×10⁻¹ cm mustbe cut into the front panel of a displayunit. The tolerance is1.0×10⁻³ cm, which means the actual hole cannot differ by more than this quantity fromthe desired radius. If the actual holeis larger than the desired radius by the allowed tolerance,what is the difference between the actual area and the desired area of thehole?

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Physics: Acircular hole of radius 8470times10minus1 cm mustbe cut

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